c^2-5c-50=0

Solution for c^2-5c-50=0 equation:

Simplifying
c2 + -5c + -50 = 0

Reorder the terms:
-50 + -5c + c2 = 0

Solving
-50 + -5c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(10 + -1c) = 0

Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve:

Simplifying
-5 + -1c = 0

Solving
-5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1c = 0 + 5
-1c = 0 + 5

Combine like terms: 0 + 5 = 5
-1c = 5

Divide each side by '-1'.
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(10 + -1c)' equal to zero and attempt to solve:

Simplifying
10 + -1c = 0

Solving
10 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1c = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1c = 0 + -10
-1c = 0 + -10

Combine like terms: 0 + -10 = -10
-1c = -10

Divide each side by '-1'.
c = 10

Simplifying
c = 10
Solution
c = {-5, 10}